( ESNUG 293 Item 10 ) --------------------------------------------- [6/10/98]

Subject: Electromigration Failures, Reliability, & Metal Coverage

> Can someone, please, explain me OR point me to articles on the subject
> WHY metal coverage is needed.  I know that if such not done, metal etching
> will cause minimum-width metals to disconect due to over-etch, BUT would
> like to understand WHY..?
>
>   - Yehuda D. Yizraeli
>     Zoran Microelectronics Ltd.                Haifa, Israel


From: David Shain <dshain@nr.infi.net>

If Aluminimum is usually half to 1 micron thick & if there is a severe
step, like into a contact, or over some underlying topography, thinning
can occur.  If you only have 10% step coverage then the metal will only
be .05  to .1 microns.  There is a problem with this well before
"catastrophic" disconnect.  The problem is a reliability issue associated
with high current density.  Alumimum interconnects are subject to
degrading when subjected to high current densities. when a line is
thinned to 10% of it's designed thickness, that means the current
density can be 10 times higher than allowed.  The aluminimum line will
fail as a result.

In the days of wet etch, over etch was a problem with thin lines, but
now with dry etch you usually will not overetch a thing line.

There are also specification on minimum step coverage for yield reasons
that must be met.

  - David Shain

         ----    ----    ----    ----    ----    ----   ----

From: jws@billy.mlb.semi.harris.com (James W. Swonger)

Electromigration failures are the probable basis of the question.  High
reliability circuits generally are designed to meet a maximum current
density in interconnect.  The metal thickness and width are of interest;
typically the highest current density is found where the interconnect metal
traverses an oxide step topographic feature (contact sidewall, diffusion
oxide cut, poly+ILD, etc.). 

There are really two fundamental requirements for interconnect: mechanical 
integrity and electrical integrity.  The mechanical (ability to hang
together through thermal cycling/shock, stress voids from creep due to
internal tensile stress, etc.) requires some minimum thickness (approx 2kA
is my rule of thumb).  Electrical integrity is design & application
dependent; for a decent aluminum system you are looking for a worst case
avg. current density of 2E5 A/cm2 taking into account duty cycle,
topography, & a peak current density of no more than 10X that, maybe less.

The ability of materials to carry high currents for long periods of time
varies with:

  - composition: refractory metals are not seen to fail at all; gold
    and aluminum are known to electromigrate.  Metals of intermediate
    melting point and hardness can be expected to have some electro-
    migration behavior, I think; e.g. copper will probably fall 
    between aluminum and molybdenum somewhere.  Aluminum interconnect
    often contains trace amounts (1-2%) of copper to improve its 
    current density tolerance.  Maximum actual current density is
    determined by long term life test under stress, but the Mil
    specs impose a fixed limit.  Thus in many cases we require only 
    that the process we are designing in exceeds that value.

  - temperature: high temperature is a strong accelerating factor in
    electromigration wearout; this mechanism is the primary reason 
    for most IC processes' 175C junction temperature rating.  Search
    "Black's Law", "electromigration" in reliability physics periodicals.

  - area: notching and thinning of metal lines, designed widths and
    processing nonidealities.

The Mil specs call out step coverage percentages as a means of setting some
standards for interconnect step coverage processing acceptance.  This is
somewhat wrongheaded, since you can have a thin metal at 70% that's got less
cross-sectional area than thicker metal at 50%.  But rules are rules, until
you negotiate.

  - James W. Swonger
    Harris Semiconductor                          Melbourne, Florida



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